1
2
3
逹 4
偒 逹 5
槪 6
7
8
厠 9
10
1 2 亘 11
12
13
14
15
16
17
逹 18
19
20
21
22
23
24
25
n ( n j+ 1) j j= 1 4 (4 3+ 1) j = 2/10 = 0.2 j= 1 26
27
28
86 11 5 33 87 3 25 9 89 5 17 16 93 2 25 3 96 6 6 9 3 ( ) 90% 3 10 ( ) 60% 10 40% 29
30
31
32
84 11 1 28 86 11 5 33 92 12 31 28 96 6 6 9 ( ) A B C D 33
(Corresponding author) n j = ( n j+ 1) j n j= 1 B 20,000 B 4 3 = 4 (4 3+ 1) j = 2/10 = 0.2 j= 1 B 20,000 20,000 (0.2) = 4,000 34
89 1 13 89 4 19 91 1 16 3 96 6 6 9 35