untitled

Similar documents
untitled

untitled

untitled

untitled

untitled

untitled

( )

untitled

untitled

习 题 7

! # %& ( %! & & + %!, ( Α Α Α Α Χ Χ Α Χ Α Α Χ Α Α Α Α

! # %! #! #! # % + &, % % ) %. /! # 0 1


& &((. ) ( & ) 6 0 &6,: & ) ; ; < 7 ; = = ;# > <# > 7 # 0 7#? Α <7 7 < = ; <

& & ) ( +( #, # &,! # +., ) # % # # % ( #

% %! # % & ( ) % # + # # % # # & & % ( #,. %

untitled

. () ; () ; (3) ; (4).. () : P.4 3.4; P. A (3). () : P. A (5)(6); B. (3) : P.33 A (9),. (4) : P. B 5, 7(). (5) : P.8 3.3; P ; P.89 A 7. (6) : P.


WL100014ZW.PDF

bingdian001.com

: ; # 7 ( 8 7


# # # #!! % &! # % 6 & () ) &+ & ( & +, () + 0. / & / &1 / &1, & ( ( & +. 4 / &1 5,

koji-13.dvi

u -, θ = 0, k gu = 2 ln E v, v -, θ = π 2, k gv = dθ 2 E. 2. r(u, v) = {a cos u cos v, a cos u sin v, a sin u} k g = sin u dv, θ. E = a 2, F = 0, = a

!! # % & ( )!!! # + %!!! &!!, # ( + #. ) % )/ # & /.

! Ν! Ν Ν & ] # Α. 7 Α ) Σ ),, Σ 87 ) Ψ ) +Ε 1)Ε Τ 7 4, <) < Ε : ), > 8 7

lim f(x) lim g(x) 0, lim f(x) g(x),

&! +! # ## % & #( ) % % % () ) ( %

untitled

微积分 授课讲义

!! )!!! +,./ 0 1 +, 2 3 4, # 8,2 6, 2 6,,2 6, 2 6 3,2 6 5, 2 6 3, 2 6 9!, , 2 6 9, 2 3 9, 2 6 9,

Ρ Τ Π Υ 8 ). /0+ 1, 234) ς Ω! Ω! # Ω Ξ %& Π 8 Δ, + 8 ),. Ψ4) (. / 0+ 1, > + 1, / : ( 2 : / < Α : / %& %& Ζ Θ Π Π 4 Π Τ > [ [ Ζ ] ] %& Τ Τ Ζ Ζ Π

悖论

) & ( +,! (# ) +. + / & 6!!!.! (!,! (! & 7 6!. 8 / ! (! & 0 6! (9 & 2 7 6!! 3 : ; 5 7 6! ) % (. ()

,!! #! > 1? = 4!! > = 5 4? 2 Α Α!.= = 54? Β. : 2>7 2 1 Χ! # % % ( ) +,. /0, , ) 7. 2

5 (Green) δ

4= 8 4 < 4 ϑ = 4 ϑ ; 4 4= = 8 : 4 < : 4 < Κ : 4 ϑ ; : = 4 4 : ;


, ( 6 7 8! 9! (, 4 : : ; 0.<. = (>!? Α% ), Β 0< Χ 0< Χ 2 Δ Ε Φ( 7 Γ Β Δ Η7 (7 Ι + ) ϑ!, 4 0 / / 2 / / < 5 02




., /,, 0!, + & )!. + + (, &, & 1 & ) ) 2 2 ) 1! 2 2

! /. /. /> /. / Ε Χ /. 2 5 /. /. / /. 5 / Φ0 5 7 Γ Η Ε 9 5 /


untitled

PowerPoint 演示文稿

, & % # & # # & % & + # & # # # & # % #,

8 9 8 Δ 9 = 1 Η Ι4 ϑ< Κ Λ 3ϑ 3 >1Ε Μ Ε 8 > = 8 9 =


Β 8 Α ) ; %! #?! > 8 8 Χ Δ Ε ΦΦ Ε Γ Δ Ε Η Η Ι Ε ϑ 8 9 :! 9 9 & ϑ Κ & ϑ Λ &! &!! 4!! Μ Α!! ϑ Β & Ν Λ Κ Λ Ο Λ 8! % & Π Θ Φ & Ρ Θ & Θ & Σ ΠΕ # & Θ Θ Σ Ε

/ Ν #, Ο / ( = Π 2Θ Ε2 Ρ Σ Π 2 Θ Ε Θ Ρ Π 2Θ ϑ2 Ρ Π 2 Θ ϑ2 Ρ Π 23 8 Ρ Π 2 Θϑ 2 Ρ Σ Σ Μ Π 2 Θ 3 Θ Ρ Κ2 Σ Π 2 Θ 3 Θ Ρ Κ Η Σ Π 2 ϑ Η 2 Ρ Π Ρ Π 2 ϑ Θ Κ Ρ Π



!!! #! )! ( %!! #!%! % + % & & ( )) % & & #! & )! ( %! ),,, )

) Μ <Κ 1 > < # % & ( ) % > Χ < > Δ Χ < > < > / 7 ϑ Ν < Δ 7 ϑ Ν > < 8 ) %2 ): > < Ο Ε 4 Π : 2 Θ >? / Γ Ι) = =? Γ Α Ι Ρ ;2 < 7 Σ6 )> Ι= Η < Λ 2 % & 1 &

第四章 数值积分与数值微分

> # ) Β Χ Χ 7 Δ Ε Φ Γ 5 Η Γ + Ι + ϑ Κ 7 # + 7 Φ 0 Ε Φ # Ε + Φ, Κ + ( Λ # Γ Κ Γ # Κ Μ 0 Ν Ο Κ Ι Π, Ι Π Θ Κ Ι Π ; 4 # Ι Π Η Κ Ι Π. Ο Κ Ι ;. Ο Κ Ι Π 2 Η

9!!!! #!! : ;!! <! #! # & # (! )! & ( # # #+

%% &% %% %% %% % () (! #! %!!!!!!!%! # %& ( % & ) +, # (.. /,) %& 0

8 9 < ; ; = < ; : < ;! 8 9 % ; ϑ 8 9 <; < 8 9 <! 89! Ε Χ ϑ! ϑ! ϑ < ϑ 8 9 : ϑ ϑ 89 9 ϑ ϑ! ϑ! < ϑ < = 8 9 Χ ϑ!! <! 8 9 ΧΧ ϑ! < < < < = 8 9 <! = 8 9 <! <

! + +, ) % %.!&!, /! 0! 0 # ( ( # (,, # ( % 1 2 ) (, ( 4! 0 & 2 /, # # ( &

= Υ Ξ & 9 = ) %. Ο) Δ Υ Ψ &Ο. 05 3; Ι Ι + 4) &Υ ϑ% Ο ) Χ Υ &! 7) &Ξ) Ζ) 9 [ )!! Τ 9 = Δ Υ Δ Υ Ψ (

PowerPoint Presentation

. /!Ι Γ 3 ϑκ, / Ι Ι Ι Λ, Λ +Ι Λ +Ι

2 2 Λ ϑ Δ Χ Δ Ι> 5 Λ Λ Χ Δ 5 Β. Δ Ι > Ε!!Χ ϑ : Χ Ε ϑ! ϑ Β Β Β ϑ Χ Β! Β Χ 5 ϑ Λ ϑ % < Μ / 4 Ν < 7 :. /. Ο 9 4 < / = Π 7 4 Η 7 4 =


! # % & # % & ( ) % % %# # %+ %% % & + %, ( % % &, & #!.,/, % &, ) ) ( % %/ ) %# / + & + (! ) &, & % & ( ) % % (% 2 & % ( & 3 % /, 4 ) %+ %( %!

考 研 数 学 三 部 曲 之 大 话 高 等 数 学 0. 考 研 数 学 高 等 数 学 部 分 其 实 就 是 一 座 大 楼 房 间 80 房 间 80 第 八 层 房 间 80 房 间 804 房 间 805 房 间 70 房 间 70 房 间 70 第 七 层 房 间 704 房 间 7

第九章 常微分方程出值问题得数值解法

,..,.,,,,,.,,.,., ,.,,.,,.,, 1,,, ; 2,,,,.,,,,.,,.,,,.,.,.,,.,.,,,.,,,.,,,,.,.,,,, i

《分析化学辞典》_数据处理条目_1.DOC

4 # = # 4 Γ = 4 0 = 4 = 4 = Η, 6 3 Ι ; 9 Β Δ : 8 9 Χ Χ ϑ 6 Κ Δ ) Χ 8 Λ 6 ;3 Ι 6 Χ Δ : Χ 9 Χ Χ ϑ 6 Κ


第9章 排队论

(p.29). (a) F Qq r 2 ()() N (b) Q 2 r 2 F ( 2 )() Q 0 5 C 2. (a) F (b) F 3. 7 (p.42). (a) T (b) F (c) T 2. (a) A (b) (c) 4. (a) 4 (b) (

考 纲 解 读 14 浙 江 省 普 通 高 考 语 文 科 考 纲 研 读 吴 美 琴 今 年 的 考 试 说 明, 我 用 了 八 个 字 进 行 概 括, 那 就 是 稳 中 微 调, 关 注 生 活 稳 中 微 调 :14 年 的 语 文 考 试 说 明 是 近 几 年 来 调 整 幅 度


! # Χ Η Ι 8 ϑ 8 5 Χ ΚΗ /8 Η/. 6 / Λ. /. Η /. Α Α + Α 0. Η 56 + Α : Α Μ / Η +9 Δ /. : Α : ϑ. Η. /5 % Χ

.., + +, +, +, +, +, +,! # # % ( % ( / 0!% ( %! %! % # (!) %!%! # (!!# % ) # (!! # )! % +,! ) ) &.. 1. # % 1 ) 2 % 2 1 #% %! ( & # +! %, %. #( # ( 1 (

# % & ) ) & + %,!# & + #. / / & ) 0 / 1! 2

<313034A4BDB67DA4C0B56FBA5DB3E65FBD64A5BB2E786C7378>


( )... ds.....

論鄭玄對《禮記‧月令》的考辨

Ⅰ Ⅱ 1 2 Ⅲ Ⅳ

# # 4 + % ( ) ( /! 3 (0 0 (012 0 # (,!./ %

( ) Wuhan University

4 A C n n, AA = A A, A,,, Hermite, Hermite,, A, A A, A, A 4 (, 4,, A A, ( A C n n, A A n, 4 A = (a ij n n, λ, λ,, λ n A n n ( (Schur λ i n

untitled

工程硕士网络辅导第一讲

untitled

PowerPoint 演示文稿

E = B B = B = µ J + µ ε E B A A E B = B = A E = B E + A ϕ E? = ϕ E + A = E + A = E + A = ϕ E = ϕ A E E B J A f T = f L =.2 A = B A Aϕ A A = A + ψ ϕ ϕ

# #! ) ( ( +,! %,! ( # # %& % ( ) +! +, +. /


數學教育學習領域

精 勤 求 学 自 强 不 息 Born to win! 5 具 有 听 觉 的 不 足 6 个 月 的 婴 儿 能 迅 速 分 辨 相 似 的 语 音, 不 仅 仅 是 那 些 抚 养 这 些 婴 儿 的 人 使 用 的 语 言 的 声 音 而 年 轻 人 只 能 在 他 们 经 常 使 用 的

Transcription:

4 6 4 4 ( n ) f( ) = lim n n +, f ( ) = = f( ) = ( ) ( n ) f( ) = lim = lim n = = n n + n + n f ( ), = =,, lim f ( ) = lim = f() = f ( ) y ( ) = t + t+ y = t t +, y = y( ) dy dy dt t t = = = = d d t + t + t +, dt 4 = = = d dt d d t + ( t + ) ( t + ) d y d dy dt t, d y d < t < = + +, t <, (,) ( t = = (,] t t )

+ d = + d sct tan t sc = t dt = dt= sct tan t d t = = = = t + ( ) dt dt arcsin t t t t z 4 z = z(, y) z = + y, z + z = y z z = + y y z, y z z z = ( ) z z z = ( ) + y y z = + z z z = y + z z z z + + = = z y + z F(, y, z) = + y z = F z = F F = y z z = ( ) F z = = = F (+ ) + z z z z z

F z = y = = F z z y (+ ) + z z z z + = + z z = y + + z dz = (d dz) + dy z z = d+ dy dz z z ( + ) dz = d + dy z dz = d + dy z z + + z = + z z z = z y + z z + = y 6 5 ( y+ ) d dy = y = = 5 y = + 5 dy y = d dy y = d dy = d y ln y = ln + ln c y = c y = c( ) c ( ) + c ( ) ( ) c = c ( ) =

5 c ( ) = d+ C= + C 5 5 y = ( + C) = C + 5 5 6 y = C = 5 = y = + 5 dy y = d d d y = d+ C ln ln = d+ C 5 = d+ C = + C 5 6 y() = C = 5 y = + 5 6 A =, B ABA = BA + E, A A, E, B = 9 ABA = BA + E ABA BA = E, A E B A = E =, ( A E) BA = E,

B = = = = A E A ( ) ( ) 9 A A = A A ABA = BA + E AB A A = B A A + AA AAB= AB+ A A ( A E) B= A A A E B = A B = = A A E 9 8 4, + 7 α = cos tdt, β = tan tdt, γ =,, A α, β, γ B α, γ, β C β, α, γ D β, γ, α sin tdt B γ lim = lim α + + sin cos tdt tdt sin = lim + cos = lim = lim = + + γ = o( α) β lim = lim + γ + tan tdt sin tdt tan = lim = lim = + + sin β = o( γ )

α γ β, B 8 f ( ) = ( ), A = f ( ), (, ) y = f( ) B = f ( ), (, ) y = f( ) C = f ( ), (, ) y = f( ) D = f ( ), (, ) y = f( ) C f ( ) = ( ), < ( ), < < f ( ) = +, < <, < <, < < f ( ) =, < < < <, f ( ), > >, f ( ), (, ) f () =,, f( ) >, =, =, (, ) y = f( ), C n 9 limln n ( + ) ( + ) ( + ) n n n n A ln d B lnd C ln( + ) d D ln ( + ) d B n limln n ( + ) ( + ) ( + ) n n n n n = limln ( )( ) ( ) n n + + + n n n

n = lim ln( ) ln( ) ( ) n n + + + + + + n n n n i = lim ln( + ) n n n i= B = ln( +) d + = t lntdt = lnd f ( ), f () >, δ > A f ( ) (, δ ) B f ( ) ( δ,) C (, δ ) f ( ) > f() D ( δ,) f ( ) > f(), C f( ) f() f () = lim >,, δ >, < δ, f( ) f() > δ > >, f ( ) > f() δ < <, f ( ) < f(), C y + y = + + sin A y = a + b+ c+ ( Asin+ Bcos ) B y = ( a + b + c + Asin + B cos ) C y = a + b+ c+ Asin D y = a + b+ c+ Acos

A y + y = λ + =, λ =± i, + = + = +,, y y ( ) y = a + b+ c i y + y = sin = I ( ), i, m y = ( Asin+ Bcos ) + = + + y y sin ( ) = + + + ( sin + cos ) y a b c A B f u, D {(, y) y y} = +, f ( y) ddy D A d f ( y) dy y y B dy f ( y) d C D sinθ dθ f( r sinθcos θ) dr sinθ D dθ f( r sinθcos θ) rdr D ( y ) f ( y ) ddy = dy f ( y ) d ( y ) + = d f ( y) dy AB = rcosθ y = rsinθ

sin f ( y) ddy θ = dθ f ( r sinθcos θ) rdr, D D y A o, A B, B C, AQ A B = C Q C D D B= A C = B C = A = A = AQ Q = D 4 A, B AB =, A A, B B A, B C A, B D A, B A

A= ( a ij) l m, B= ( b ij) m n A ( A A A ) = m b b b b b b AB = ( A A Am ) b b b m m mn n n ( b A b A b A b A ) = + + + + = m m n mn m B, b i m, j n, b A+ b A + + b A + + b A =, ij j j ij i m m A, A,, Am B B B =, B m AB = a a a B m a a a m B al al a lm B m ab + ab + + a mbm ab + ab + + ambm = = alb + alb + + almb m A a i l, j m ab + ab + ab+ + a B = ij i i ij j im m B, B,, Bm A A mn B ns AB r (A)+r (B) < n AB r (A) >, r (B) >, r (A ) < n, r (B ) < n, A B A 9 94 5

+ cos lim + cos lim = lim + cos ln + cos lim + cos ln = lim ln + cos ln = lim sin lim cos = + sin = lim = + cos 6 = lim + cos ln + cos ln = lim cos ln+ = lim cos = lim = 6 6 f ( ), +, [, ], f( ) = ( 4), f( ) = f( + ), f ( ) [,] ;, f ( ) = < + < f( ) = f( + ) = ( + )[( + ) 4] = ( + )( + 4)

f () = f( ) f() ( 4) f+ () = lim = lim = 4 + + f( ) f() ( + )( + 4) f () = lim = lim = 8 f () = f + (), = =, f ( ) = 7 + f ( ) = sint dt, f ( ) ; f ( ) + + f ( + ) = sintdt, t = u+, + + ( + ) = sin( + ) = sin = ( ), f u du u du f f ( ) sin (, + ), [, ] f ( ) = sin( + ) sin = cos sin, f ( ) =, =, =, 4 4 f( ) = 4 sintdt = 4, 4 5 5 4 4 4 4 f ( ) = sin t dt = sin t dt sin t dt = 4, f () = sin tdt=, f ( ) = ( sin t) dt =,

f ( ),, f ( ) [, ] 8 + y = =, = t( t > ) y =, Vt, () St (), = t Ft () St () Vt () () lim St t + Ft () St () = y + y d t t + + = + 4 d t + = d, t t +, Vt () = yd= d St () = Vt () t t + Ft () = y = = t t + d St () lim = lim t + Ft () t + t t + t t + = lim t + t t t t +

t t + = lim = t + t t 9 4 < a< b<, ln b ln a> ( b a) 4 ϕ ( ) = ln, ln 4 ϕ ( ) = ln ϕ ( ) =, >, ϕ ( ) <, ϕ ( ), < <, 4 4 ϕ ( ) > ϕ ( ) = =, < <, ϕ ( ), < a< b<, ϕ ( b) > ϕ ( a), 4 4 ln b b> ln a a 4 ln b ln a> ( b a) 4 ϕ ( ) = ln ln a ( a), ln 4 ϕ ( ) = ln ϕ ( ) =, >, ϕ ( ) < ϕ ( ), < <, < <, ϕ ( ) 4 4 ϕ ( ) > ϕ ( ) = =, < a < b<, ϕ ( ) > ϕ ( a) = = b ϕ ( b) > 4 > ln b ln a ( b a)

ln [ a, b], ln t lnt ϕ () t =, ϕ () t =, t t lnξ ln b ln a> ( b a), a< ξ < b ξ t >, ϕ ( t) <, ϕ () t, ϕξ ( ) > ϕ( ), lnξ ln ξ > =, ln b ln a> ( b a) 4 9g 7 m / h 6 = 6 g m / h m= 9g v = 7 m/ h t () t vt () dv m v dt = dv dv d dv = = v dt d dt d m d = dv m () t = v+ C m v() = v, () =, C = v, m () t = ( v v()) t

vt () mv 9 7 ( t) = = 5 ( m) 6 6 5 m dv m v dt = dv = dt v m t v C m =, v = v =, C = v, t vt () v m =, t + mv t mv m = vtdt ( ) = = = 5 ( m) + d d m = dt dt d d dt + = m dt r + r = m r =, r = m t C C m = + () =, d C mv = = = C = C = t m v() v dt t= m t= mv t m t () = ( ) t +

mv 9 7 ( t) = = 5 ( m) 6 6 5 m z z z z = f( y, y ) f,, y y z y = f + y f, z y = yf + f y z y = [ f ( y) + f ] + f + y f y y y y y + y [ f ( y) + f ] = 4yf + ( y ) f ++ y f + ( + y) f y y y 9 ( + a ) + + + 4 =, + ( + a) + + 4 =, + + ( + a) + 4 =, 4+ 4 + 4 + (4 + a) 4 =, a,, A, + a + a + a a a = B + a a a 4 4 4 4+ a 4a a a =, ra= ( ) < 4,, + + + 4 = η = (,,,) T, η = (,,,) T, η = (,,,) T,

η η η = + +,,, a, B + a a+ 4 4 a =, r( A ) = < 4,, + =, + =, 4 + 4 =, η = (,,,4) T, = η, + a + a A = = ( a+ ) a + a 4 4 4 4+ a A =, a = a =, a =, A, A = 4 4 4 4 + + + 4 = η = (,,,) T, η = (,,,) T, η = (,,,) T, η η η = + +,,,

a =, A, =, =, 4 = 4, η = (,,,4) T, 9 9 8 A = 7 4 4 4 6 4 9 4 4 = η, 9 4, a, A a 5 A λ λ λ λ 4 = λ 4 a λ 5 a λ 5 = ( λ ) λ 4 = ( λ ) λ a λ 5 a λ 5 λ λ λ = ( )( 8 + 8+ a) λ =, 6+ 8+ a =, a = a =, A,, 6, E A=, λ =, A

λ =, λ 8λ+ 8+ a, 8 + a = 6, a = a =, A, 4, 4, E A=, λ = 4, A