|
|
- 胡 史
- 5 years ago
- Views:
Transcription
1
2
3
4
5
6
7 W L Gates.Open Lecture The influences of the ocean on climate.scientific lecture at the 28th section of the ECWMO.WMO Bulletin. July
8
9
10
11 WCP 1 WCRP2 WCAP 3 WCIP4 WCDP
12
13 A Henderson-SellersP J Robinson. Contemporary Climatology. Longman Scientific Technical 1987
14
15
16 dt = - = 0.65 / 100m 1 1 dz
17
18 km 800km 60km D 300km EF1 F2 D E X
19
20
21 P = F 1 3 A P = Mg 1 5 A
22 P = W S = gh S = gh 1 6 S e f = E mω q = 1 9 m + m d ω mb 1mb=1000dyn/cm2 1Pa=10dyn/cm2 1mb=100Pa 1mb=1hPa Hg g/cm3g= cm/S2 1mmHg= g/cm cm/S2 0.1cm= dyn/cm2=1.333hPa mmhg hpa 1mmHg=1.33hPa=4/3hPa 1 8 1hPa=0.75mmHg=3/4mm 1 9
23 e q = p = m ω 1 11 m d = e 1 12 p - e a g/m3 g/cm3 t e
24 P1V1 P2V2 P3V3 PnVn = = = Λ = T T T T n 8 4
25 PV T = 1 14 PV T P0V0 = = R * PV = RT 1 15 T Pa m / mol R* = 273K 3 = Pam / mol K 8.31J / (mol K ) M V 1 µ V = M R T PV = M R T 1 16 µ P µ PV = M µ RT M R P = T V µ M R R V µ P = RT 1 17 R d = R * = = J / gk µ d
26 P e e ρd = ρ R ϖ = dt RϖT R * µ d R * Rω = = = Rd µ µ µ ω ω d = + = P - e R T + e 1.608(P - e) = R T 1.608R T = P R T ( e P ) d ω d ω d d e e P P e 2 P ρ = P e RdT( ) P P = R T e d 1 20 P T = e v T 1 21 P e T 1 P
27 T = T - T = e v 0 P
28
29 W/sr [] Watt per steradian
30 df = F d F = df 2 2 d λ 1 2 Fλ 1 λ 2 2 F = F d 2 3 F λ1λ 2 λ λ λ1 λ1λ F = F d λ λ Q Q a o Q r Q d + + = 1 Q Q o o
31 I I T Tb = K T e = I λt λt I λrb 2 7 I λt = I λtb 2 9 K λt IT = I Tb 2 10 K T
32
33 W/m2 AHendersonsellerselal Conlemporary Climatology W/m2
34
35 ϕ ϕ ϕ ϕ
36 S 2 8b = AC S' AB = sinh
37 I I 0 = P (2 16)
38
39
40 = C m T = m 288
41
42
43
44
45
46
47 dq=c dt-rt dp P P 2 29 C dt-rt dp P P =0 (2 30) C dt =RT dp P P T dt R p dp = T T C 0 p0 P p
48 1n T T 0 0 T = T P P R = 1 C n P P 0 P R C P 0 R 0.287J / (gk) = C J / (g K) P (2 31) T P = 2 32 T P 0 0 d = - dt i i dz 2 30 dz i d RT g g T = RT i ρ = 2 33 C Pρ C P T dp dz = -g dpi = dp dz dz = -g T i d = RT g = g i C ρrt C T Ti T P P 1 d = g (234) CP
49 2 = 98. m / s d 1005m S K 0.98K / 100m( 0.98 / 100m) 2 2 / ( ) Ldq = C dt RT dp s p 2 37 P dt RT dp L = C P C dq s 2 38 P P
50 dti dz g Ti L = C T C P p dq s dz 2 39 dti g L dqs L dq s = = γ d 2 40 dz Cp CP dz CP dz dti L dq s γ m = γ d = dz C dz m p dqs dz 0 dqs 0 0 dz dq s dz 0 dq s 0 0 m d dz dqs m dz
51 R θ = 1000 C = P T T 2 42 P P Lq θse = θ Cp
52 dq dt = Cp dt RTdP dt P dt 2 44 dt dp dt dt dt dt
53 T dt = t dt + T x dx + T y dy + T z dz 2 45 dt T dt = u T v T t + x + y + w T z 2 47 T u T v T w T = t x y z dt dt 2 48 u T v T + x y T w z
54 1 v n = Vcos60 = 30 = 15km / h 2 4 V T n = 15 = 012. / h t 500 dq 2 44 dt dt 1 RT dp = ε dt C C P dt P P dt T u T v T T = ω 2 53 dt t x y P w = dp w 0 dt
55 = g P Z RT 1 = P P g d RT = C P γ dr T g P T T Z RT T = = = P Z P Pg Z T P C P γ RT Pg RT Pg RT RT ( γ γ ) ( γ γ) Pg Pg d = d = d γ ( γ d γ) RT 0 ω 0 Pg d
56 ρ i a = ρ g 2 58 ρ i = P i = P i P i = P RT RT i Ti T a = T g 2 59
57 γ γ d a = g Z 2 60 T
58 θ 2 42 Z 1 θ 1 T R 1 = θ Z T Z C P 1 T RT = T Z CPP P Z P Z P = ρg = g P Z RT R T P g = = γ C P Z C P P P d 1 θ 1 T = + γ d θ Z T Z θ θ = ( γ γ d Z T ) θ θ 0 ( d ) 0 0 ( d ) Z Z θ 0 0 ( d ) = 0 Z θ 0 Z γ γ m a = g Z 2 61 T
59 se 0 0 = 0 = θ θ θ se m m se m m se m Z Z Z
60
61
62
63
64
65
66
67
68
69
70
71
72 de LE = df R T ω de L dt = E Rω T 19. 9t E = E 0e t t E = E t
73 E = E t i t at E = E β + t s i
74 Ei f i = f E
75 W A E = e P 3 9
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94 dp dz = g
95 = P R d T dp g P = dz R T d - dp 1 dz RdT h = Pg 8000 h (1+ t / 273)(m / hpa) 4 2 P
96 P2 P1 Z2 dp = ρgdz 4 3 Z1 P2 dp z2 g = P RT dz P 1 Z1 n P Z 2 2 g 1 = P RT dz Z1 1 Z2 g P = P e RT dz Z1 P P e g ( Z Z 2 1) 2 = 1 RT n P 2 g 1 = ( P RT Z Z 2 1) 1 RT Z Z n P = g P2 P1 Z2 Z1 = 18400( 1 + t / 273)log 4 6 P hPa 1.225kg/m33. 11km 4. =0.65/100m =0-56.5
97 0 0 1n P Z g g dz 1 1 P R T R n T n T z γ z γ z = = = ( ) O ( γ ) γ T T 0 0 z 0 γz Rγ Pz = P0 ( 1 ) 4 7 T 0 g 0 g Rγ
98
99
100
101
102 H = g Z ϕ 9.8 ϕ ϕ
103
104
105
106 P G = N N P N P P - - N n P - / Z 1 P A -(P Y Z X X)
107 P P P Y Z - P + Y Z = - X Y Z X X P Y Z - Y X Y P Z - X Y Z Z ϖ ϖ ϖ P + + X Y Z = - P X Y Z X i P Y j P Z k V - P - P N ϖ G ϖ G = - 1 P 4 8 ρ N 1 G G n Z = = ρ 1 ρ P n P z P - n -3 3 P = g / cm - = 1hPa / G = n N / kg n
108 S = 1 at at = V t a = 2V 2 A = 2V 4 9
109 ϕ ϕ ϕ ϖ C ϖ 2 C r ϖ V = r ϖ C = V r
110
111 ϖ dv ϖ ϖ ϖ ϖ = G + A + R + g 4 12 dt G ϖ A ϖ R ϖ g ϖ du dv dw fx =, Fy =, Fz = dt dt dt du 1 P = + 2vω sinϕ + R dt ρ x dv dt dω dt 1 P = 2uω sin ϕ + R ρ y 1 P = g + R ρ z 4 13 du 1 P = + 2vω sinϕ dt ρ x dv dt 1 P = 2uω sinϕ ρ y 1 P 0 = g ρ z 4 14
112 ϖ ϖ G = A ϖ ϖ G A 1 P = 2Vgω sinϕ ρ n 1 P Vg = ρω sinϕ n P Vg - n ϕ ϕ P n = 1hPa / = 1.293kg / m3
113 ϖ 1 P g Z G = = ρ n n g H = Z 9. 8 ϖ H G = 98. n 9. 8 H Vg = 2ω sinϕ n 4 16 ϖ ϖ 4 20 G A ϖ C ϖ ϖ ϖ G = A + C ϖ ϖ ϖ G A C V r P Vc = rωsin ϕ ± ( rω sin ϕ) ρ n ϖ ϖ ϖ G C A ϖ ϖ ϖ GC = A V = r ± r + r P ac ω sin ϕ ( ω sin ϕ) ρ n P - r n - 1 P ρ n = 0 V c = -rωsin ϕ + ( rωsinϕ) 2 r P 4 19 ρ n V ac = rωsinϕ - ( rωsinϕ) 2 + r P 4 20 ρ n c
114 ϖ G V V V ac g c ϖ ϖ G = C V r 2 1 P + = 0 ρ n P n ϕ
115 ϖ VT ϖ ϖ ϖ VT = V2 V1 ϖ ϖ ϖ V2 V1 V1 = 0 ϖ ϖ V = V 2 T ϖ g( Z2 Z1) Tm VT = ( 421) ft n m
116 ϖ ϖ ϖ V + V = V 1 T 2 ϖ ϖ ϖ V + V + V 1 T 2 ϖ V T
117
118
119
120 30 S 30 N 6 5
121
122 M = ωr 2 2 cos ϕ + urcosϕ ϕ
123
124
125
126
127 n 1 I Z = ( Φ45 Φ65 ) ϕ n 1 n 1 Φ I M = λ n 1 R cosϕ
128
129
130
131
132 f tga g T Vg = m T
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163 cascade
164
165 2 a I = b I I I = 0 2 ρ 6 2 ϕ ϕ ϕ W/m2 1372W/m2 1370W/m2 A.Henderson-sellersP.J.Robinson.Contemporary Climatology,1987 HH Z S
166 dqs = I 0 2 sinh (6.4) dt ρ dq dt s = I 0 2 (sinϕsin δ + cosϕ cosδ cosω) 6.5 ρ ϕ ϕ ϕ I 0 dqs = 2 (sin ϕ sinδ + cosϕ cosδ cos ω) dt 6 5 ρ T dt = d ω 2π T I 0 dqs = 2 (sinϕ sinδ + cosϕ cosδ cos ω) dω 6 7 2π ρ Z h AA P ZPS PZS <= cosz=sinh
167 T I Q = + ω s d 2 (sin ϕ sin δ cos ϕ cos δ cos ω ) ω 2π ρ ω0 T I 0 = ( π ρ ω sin ϕ sin δ cos ϕ cos δ sin ω ) 6 T π ϕ 0
168
169
170 MN
171
172 A.Henderson-Sellers and P.J.Robinson.Contemporary Climatology
173 A.Henderson-Sallers,P.J.Robinson.Contemporayr Climatology
174
175
176
177 P = ρg z P z = P = - g z x = 1 z P - 1 g VC T P 0 Cp P Qp = 1 0 VCpTdP = VTdP P g g C n p Qp = TiVi Pi 6 12 g i= 1 LE L P0 VqdP g n L LE = Viq i Pi 6 14 g i= 1 p
178
179
180 A.N.StrahlerA.H.Strahler.Elements of Physical Geography1979
181 1 P0 QV = VqdP g n 1 QV = Viq i Pi 6 16 g i= 1
182
183 ...Vol.13No
184
185
186
187
188
189
190
191
192
193 ϕ K A A D y + d = 100% ϕ + 14
194 + A max Ai K = + 100% 6 18a A A K A = A max A max i max + max A max 100% 6 19b + A A i - A max max
195
196
197
198
199
200 P
201
202 .CA
203 T A = λ α ' ' 6 19 αz' Q C K T p = pρ α 6 20 αz αq LE = LK 6 21 αz αt' A αz' ' K' = λ 6 22 ρ' C'
204 αt C αz P dq 6 22 L dz K dq dz
205 p 1 1
206
207 A.Henderson-Sellers and P.J.Robinson.Contemporary Climatology.Longman ScientificTechnical
208
209
210
211
212
213
214
215 r 6cm 10 cm 25 r 6cm 10 cm 25
216
217
218 p p p p p
219 p p p
220
221
222
223
224
225
226
227
228
229
230
231
232
233
234
235
236
237 r5 mm
238
239
240
241 ( ) ( ) O 2 3 ( R 25 E 65 K 136 J T 225 P 280 C 345 D 395 S 435 O Z ) ( ( ) ) ( ) ( O2 3 10% ) O2 1% ( )
242
243
244
245
246
247 Trends'93Published by CDIAC
248
249
250 A. C. E. B. - D. F. 8 6
251
252
253
254 1983
255
256
257
258
259
260
261 CH4 CO2 2.1 N2O CO2 206 CFCs CO2
262
263
264
265 F G F G
266
267
268 n E H µ = KC 2
269 e RH u r u r
270 eu-r (hpa) RHu-r( ) e u r
271
272
273
274
275
ο HOH 104 31 O H 0.9568 A 1 1 109 28 1.01A ο Q C D t z = ρ z 1 1 z t D z z z t Qz = 1 2 z D z 2 2 Cl HCO SO CO 3 4 3 3 4 HCO SO 2 3 65 2 1 F0. 005H SiO0. 032M 0. 38 T4 9 ( K + Na) Ca 6 0 2 7 27 1-9
More informationm0 m = v2 1 c 2 F G m m 1 2 = 2 r m L T = 2 π ( m g 4 ) m m = 1 F AC F BC r F r F l r = sin sinl l F = h d G + S 2 = t v h = t 2 l = v 2 t t h = v = at v = gt t 1 l 1 a t g = t sin α 1 1 a = gsinα
More informationP r = 1 + ecosθ 2 V = V + V 1 2 2V1V2 cosθ 2 2 = ( V V ) + 2V V ( 1 cos θ) 1 2 1 2 40000 V = 0. 5( / ) 24 60 60 λ m = 5100A = 0.51 Å 2 u e d s 3 1 e uud udd 3 2 3 e 1 3 e V = 2 9. 8 2000 = 198 V
More informationE = B B = B = µ J + µ ε E B A A E B = B = A E = B E + A ϕ E? = ϕ E + A = E + A = E + A = ϕ E = ϕ A E E B J A f T = f L =.2 A = B A Aϕ A A = A + ψ ϕ ϕ
.................................2.......................... 2.3.......................... 2.4 d' Alembet...................... 3.5......................... 4.6................................... 5 2 5
More informationΖ # % & ( ) % + & ) / 0 0 1 0 2 3 ( ( # 4 & 5 & 4 2 2 ( 1 ) ). / 6 # ( 2 78 9 % + : ; ( ; < = % > ) / 4 % 1 & % 1 ) 8 (? Α >? Β? Χ Β Δ Ε ;> Φ Β >? = Β Χ? Α Γ Η 0 Γ > 0 0 Γ 0 Β Β Χ 5 Ι ϑ 0 Γ 1 ) & Ε 0 Α
More information# # # #!! % &! # % 6 & () ) &+ & ( & +, () + 0. / & / &1 / &1, & ( ( & +. 4 / &1 5,
# # # #!! % &! # % 6 & () ) &+ & ( & +, () + 0. / & / &1 / &1, & ( 0 2 3 ( & +. 4 / &1 5, !! & 6 7! 6! &1 + 51, (,1 ( 5& (5( (5 & &1 8. +5 &1 +,,( ! (! 6 9/: ;/:! % 7 3 &1 + ( & &, ( && ( )
More information!! # % & ( )!!! # + %!!! &!!, # ( + #. ) % )/ # & /.
! # !! # % & ( )!!! # + %!!! &!!, # ( + #. ) % )/ # & /. #! % & & ( ) # (!! /! / + ) & %,/ #! )!! / & # 0 %#,,. /! &! /!! ) 0+(,, # & % ) 1 # & /. / & %! # # #! & & # # #. ).! & #. #,!! 2 34 56 7 86 9
More information( )
( ) * 22 2 29 2......................................... 2.2........................................ 3 3..................................... 3.2.............................. 3 2 4 2........................................
More information! /. /. /> /. / Ε Χ /. 2 5 /. /. / /. 5 / Φ0 5 7 Γ Η Ε 9 5 /
! # %& ( %) & +, + % ) # % % ). / 0 /. /10 2 /3. /!. 4 5 /6. /. 7!8! 9 / 5 : 6 8 : 7 ; < 5 7 9 1. 5 /3 5 7 9 7! 4 5 5 /! 7 = /6 5 / 0 5 /. 7 : 6 8 : 9 5 / >? 0 /.? 0 /1> 30 /!0 7 3 Α 9 / 5 7 9 /. 7 Β Χ9
More information-2 4 - cr 5 - 15 3 5 ph 6.5-8.5 () 450 mg/l 0.3 mg/l 0.1 mg/l 1.0 mg/l 1.0 mg/l () 0.002 mg/l 0.3 mg/l 250 mg/l 250 mg/l 1000 mg/l 1.0 mg/l 0.05 mg/l 0.05 mg/l 0.01 mg/l 0.001 mg/l 0.01 mg/l () 0.05 mg/l
More information! # % & # % & ( ) % % %# # %+ %% % & + %, ( % % &, & #!.,/, % &, ) ) ( % %/ ) %# / + & + (! ) &, & % & ( ) % % (% 2 & % ( & 3 % /, 4 ) %+ %( %!
! # # % & ( ) ! # % & # % & ( ) % % %# # %+ %% % & + %, ( % % &, & #!.,/, % &, ) ) ( % %/ ) 0 + 1 %# / + & + (! ) &, & % & ( ) % % (% 2 & % ( & 3 % /, 4 ) %+ %( %! # ( & & 5)6 %+ % ( % %/ ) ( % & + %/
More information! # % & ( & # ) +& & # ). / 0 ) + 1 0 2 & 4 56 7 8 5 0 9 7 # & : 6/ # ; 4 6 # # ; < 8 / # 7 & & = # < > 6 +? # Α # + + Β # Χ Χ Χ > Δ / < Ε + & 6 ; > > 6 & > < > # < & 6 & + : & = & < > 6+?. = & & ) & >&
More information& & ) ( +( #, # &,! # +., ) # % # # % ( #
! # % & # (! & & ) ( +( #, # &,! # +., ) # % # # % ( # Ι! # % & ( ) & % / 0 ( # ( 1 2 & 3 # ) 123 #, # #!. + 4 5 6, 7 8 9 : 5 ; < = >?? Α Β Χ Δ : 5 > Ε Φ > Γ > Α Β #! Η % # (, # # #, & # % % %+ ( Ι # %
More informationWL100014ZW.PDF
A Z 1 238 H U 1 92 1 2 3 1 1 1 H H H 235 238 92 U 92 U 1.1 2 1 H 3 1 H 3 2 He 4 2 He 6 3 Hi 7 3 Hi 9 4 Be 10 5 B 2 1.113MeV H 1 4 2 He B/ A =7.075MeV 4 He 238 94 Pu U + +5.6MeV 234 92 2 235 U + 200MeV
More informationuntitled
4 6 4 4 ( n ) f( ) = lim n n +, f ( ) = = f( ) = ( ) ( n ) f( ) = lim = lim n = = n n + n + n f ( ), = =,, lim f ( ) = lim = f() = f ( ) y ( ) = t + t+ y = t t +, y = y( ) dy dy dt t t = = = = d d t +
More information% %! # % & ( ) % # + # # % # # & & % ( #,. %
!!! # #! # % & % %! # % & ( ) % # + # # % # # & & % ( #,. % , ( /0 ) %, + ( 1 ( 2 ) + %, ( 3, ( 123 % & # %, &% % #, % ( ) + & &% & ( & 4 ( & # 4 % #, #, ( ) + % 4 % & &, & & # / / % %, &% ! # #! # # #
More informationuntitled
arctan lim ln +. 6 ( + ). arctan arctan + ln 6 lim lim lim y y ( ln ) lim 6 6 ( + ) y + y dy. d y yd + dy ln d + dy y ln d d dy, dy ln d, y + y y dy dy ln y+ + d d y y ln ( + ) + dy d dy ln d dy + d 7.
More informationuntitled
5 55-% 8-8 8-5% - 7 7 U- lim lim u k k k u k k k k ` k u k k lim.7. 8 e e. e www.tighuatutor.com 5 79 755 [ e ] e e [ e ] e e e. --7 - u z dz d d dz u du d 8d d d d dz d d d d. 5-5 A E B BA B E B B BA
More information《分析化学辞典》_数据处理条目_1.DOC
3 4 5 6 7 χ χ m.303 B = f log f log C = m f = = m = f m C = + 3( m ) f = f f = m = f f = n n m B χ α χ α,( m ) H µ σ H 0 µ = µ H σ = 0 σ H µ µ H σ σ α H0 H α 0 H0 H0 H H 0 H 0 8 = σ σ σ = ( n ) σ n σ /
More informationa b a = a ϕ λ ϕ λ ρ δ ρ δ ϕ λ M' J' x' = = m MJ x M' K' y' = = n MK y x' x = m 2-1 y' y = n 2 2 x + y = 1 2-2 2 2 x' y' 2 + 2 = 1 m n µ = ds ' ds 2 2 2 2 m + n = a + b 2-3 mnsinθ = ab 2-4 2 2 2 (
More informationΡ Τ Π Υ 8 ). /0+ 1, 234) ς Ω! Ω! # Ω Ξ %& Π 8 Δ, + 8 ),. Ψ4) (. / 0+ 1, > + 1, / : ( 2 : / < Α : / %& %& Ζ Θ Π Π 4 Π Τ > [ [ Ζ ] ] %& Τ Τ Ζ Ζ Π
! # % & ( ) + (,. /0 +1, 234) % 5 / 0 6/ 7 7 & % 8 9 : / ; 34 : + 3. & < / = : / 0 5 /: = + % >+ ( 4 : 0, 7 : 0,? & % 5. / 0:? : / : 43 : 2 : Α : / 6 3 : ; Β?? : Α 0+ 1,4. Α? + & % ; 4 ( :. Α 6 4 : & %
More information&! +! # ## % & #( ) % % % () ) ( %
&! +! # ## % & #( ) % % % () ) ( % &! +! # ## % & #( ) % % % () ) ( % ,. /, / 0 0 1,! # % & ( ) + /, 2 3 4 5 6 7 8 6 6 9 : / ;. ; % % % % %. ) >? > /,,
More informationuntitled
1 2.1 ΔP r n n r ΔV ΔS ΔF r V s r f lim ΔV 0 r ΔF ρδv m/s 2 2 2 ΔP r n n r ΔV ΔS ΔF r V s r n lim Δ S 0 r ΔP ΔS n Pa 3 lim ΔS 0 r ΔP ΔS B ΔS ΔP r s 4 2 r f 1 ρ δ δδ 6 δ n δ O δ B 1 δδ 2 1 δδ 2 A 5 3 1
More information! # %& ( %! & & + %!, ( Α Α Α Α Χ Χ Α Χ Α Α Χ Α Α Α Α
Ε! # % & ( )%! & & + %!, (./ 0 1 & & 2. 3 &. 4/. %! / (! %2 % ( 5 4 5 ) 2! 6 2! 2 2. / & 7 2! % &. 3.! & (. 2 & & / 8 2. ( % 2 & 2.! 9. %./ 5 : ; 5. % & %2 2 & % 2!! /. . %! & % &? & 5 6!% 2.
More information2 2 Λ ϑ Δ Χ Δ Ι> 5 Λ Λ Χ Δ 5 Β. Δ Ι > Ε!!Χ ϑ : Χ Ε ϑ! ϑ Β Β Β ϑ Χ Β! Β Χ 5 ϑ Λ ϑ % < Μ / 4 Ν < 7 :. /. Ο 9 4 < / = Π 7 4 Η 7 4 =
! # % # & ( ) % # ( +, & % # ) % # (. / ). 1 2 3 4! 5 6 4. 7 8 9 4 : 2 ; 4 < = = 2 >9 3? & 5 5 Α Α 1 Β ΧΔ Ε Α Φ 7 Γ 9Η 8 Δ Ι > Δ / ϑ Κ Α Χ Ε ϑ Λ ϑ 2 2 Λ ϑ Δ Χ Δ Ι> 5 Λ Λ Χ Δ 5 Β. Δ Ι > Ε!!Χ ϑ : Χ Ε ϑ!
More information!! )!!! +,./ 0 1 +, 2 3 4, # 8,2 6, 2 6,,2 6, 2 6 3,2 6 5, 2 6 3, 2 6 9!, , 2 6 9, 2 3 9, 2 6 9,
! # !! )!!! +,./ 0 1 +, 2 3 4, 23 3 5 67 # 8,2 6, 2 6,,2 6, 2 6 3,2 6 5, 2 6 3, 2 6 9!, 2 6 65, 2 6 9, 2 3 9, 2 6 9, 2 6 3 5 , 2 6 2, 2 6, 2 6 2, 2 6!!!, 2, 4 # : :, 2 6.! # ; /< = > /?, 2 3! 9 ! #!,!!#.,
More informationPowerPoint 演示文稿
. ttp://www.reej.com 4-9-9 4-9-9 . a b { } a b { }. Φ ϕ ϕ ϕ { } Φ a b { }. ttp://www.reej.com 4-9-9 . ~ ma{ } ~ m m{ } ~ m~ ~ a b but m ~ 4-9-9 4 . P : ; Φ { } { ϕ ϕ a a a a a R } P pa ttp://www.reej.com
More information泵与风机
100m 3 /h 980.6kPa 5-1 10 1 1 2 3 5 4 3 5-1 1 2 3 4 5 10 6 7 8 9 10 11 12 3 4 5 7 209 5-2 5-2 120 1 5-1 n S A ASn q V Tm = 5-1 60 q Vm f i(1 ) ASn = 2 A η m 3 /s V 60 iαasn q = η 60 i m 3 /s 5-2 Vm V η
More information& &((. ) ( & ) 6 0 &6,: & ) ; ; < 7 ; = = ;# > <# > 7 # 0 7#? Α <7 7 < = ; <
! # %& ( )! & +, &. / 0 # # 1 1 2 # 3 4!. &5 (& ) 6 0 0 2! +! +( &) 6 0 7 & 6 8. 9 6 &((. ) 6 4. 6 + ( & ) 6 0 &6,: & )6 0 3 7 ; ; < 7 ; = = ;# > 7 # 0 7#? Α
More information., /,, 0!, + & )!. + + (, &, & 1 & ) ) 2 2 ) 1! 2 2
! # &!! ) ( +, ., /,, 0!, + & )!. + + (, &, & 1 & ) ) 2 2 ) 1! 2 2 ! 2 2 & & 1 3! 3, 4 45!, 2! # 1 # ( &, 2 &, # 7 + 4 3 ) 8. 9 9 : ; 4 ), 1!! 4 4 &1 &,, 2! & 1 2 1! 1! 1 & 2, & 2 & < )4 )! /! 4 4 &! &,
More information第一章 绪论
1-1 1-1 1-5 0.05 1-6 1 60mm 1.5W/(m K) 5-5 m C 1-7 1cm, 0 m 1.04W/(m K) C C 50 50 4.09 10 kj/kg C 1-9 =69 C f =0 w C =14mm d 80mm 8.5W 1-11 10mm 0 C 85 C ( ) 175 W m K 1mm 1-14 T0 0K T = w 50K ε = 0. 7
More information4= 8 4 < 4 ϑ = 4 ϑ ; 4 4= = 8 : 4 < : 4 < Κ : 4 ϑ ; : = 4 4 : ;
! #! % & ( ) +!, + +!. / 0 /, 2 ) 3 4 5 6 7 8 8 8 9 : 9 ;< 9 = = = 4 ) > (/?08 4 ; ; 8 Β Χ 2 ΔΔ2 4 4 8 4 8 4 8 Ε Φ Α, 3Γ Η Ι 4 ϑ 8 4 ϑ 8 4 8 4 < 8 4 5 8 4 4
More information! Ν! Ν Ν & ] # Α. 7 Α ) Σ ),, Σ 87 ) Ψ ) +Ε 1)Ε Τ 7 4, <) < Ε : ), > 8 7
!! # & ( ) +,. )/ 0 1, 2 ) 3, 4 5. 6 7 87 + 5 1!! # : ;< = > < < ;?? Α Β Χ Β ;< Α? 6 Δ : Ε6 Χ < Χ Α < Α Α Χ? Φ > Α ;Γ ;Η Α ;?? Φ Ι 6 Ε Β ΕΒ Γ Γ > < ϑ ( = : ;Α < : Χ Κ Χ Γ? Ε Ι Χ Α Ε? Α Χ Α ; Γ ;
More information, ( 6 7 8! 9! (, 4 : : ; 0.<. = (>!? Α% ), Β 0< Χ 0< Χ 2 Δ Ε Φ( 7 Γ Β Δ Η7 (7 Ι + ) ϑ!, 4 0 / / 2 / / < 5 02
! # % & ( ) +, ) %,! # % & ( ( ) +,. / / 01 23 01 4, 0/ / 5 0 , ( 6 7 8! 9! (, 4 : : ; 0.!? Α% ), Β 0< Χ 0< Χ 2 Δ Ε Φ( 7 Γ Β Δ 5 3 3 5 3 1 Η7 (7 Ι + ) ϑ!, 4 0 / / 2 / 3 0 0 / < 5 02 Ν!.! %) / 0
More informationΠ Ρ! #! % & #! (! )! + %!!. / 0% # 0 2 3 3 4 7 8 9 Δ5?? 5 9? Κ :5 5 7 < 7 Δ 7 9 :5? / + 0 5 6 6 7 : ; 7 < = >? : Α8 5 > :9 Β 5 Χ : = 8 + ΑΔ? 9 Β Ε 9 = 9? : ; : Α 5 9 7 3 5 > 5 Δ > Β Χ < :? 3 9? 5 Χ 9 Β
More information!!! #! )! ( %!! #!%! % + % & & ( )) % & & #! & )! ( %! ),,, )
! # % & # % ( ) & + + !!! #! )! ( %!! #!%! % + % & & ( )) % & & #! & )! ( %! ),,, ) 6 # / 0 1 + ) ( + 3 0 ( 1 1( ) ) ( 0 ) 4 ( ) 1 1 0 ( ( ) 1 / ) ( 1 ( 0 ) ) + ( ( 0 ) 0 0 ( / / ) ( ( ) ( 5 ( 0 + 0 +
More information/ Ν #, Ο / ( = Π 2Θ Ε2 Ρ Σ Π 2 Θ Ε Θ Ρ Π 2Θ ϑ2 Ρ Π 2 Θ ϑ2 Ρ Π 23 8 Ρ Π 2 Θϑ 2 Ρ Σ Σ Μ Π 2 Θ 3 Θ Ρ Κ2 Σ Π 2 Θ 3 Θ Ρ Κ Η Σ Π 2 ϑ Η 2 Ρ Π Ρ Π 2 ϑ Θ Κ Ρ Π
! # #! % & ( ) % # # +, % #. % ( # / ) % 0 1 + ) % 2 3 3 3 4 5 6 # 7 % 0 8 + % 8 + 9 ) 9 # % : ; + % 5! + )+)#. + + < ) ( # )# < # # % 0 < % + % + < + ) = ( 0 ) # + + # % )#!# +), (? ( # +) # + ( +. #!,
More information08-01.indd
1 02 04 08 14 20 27 31 35 40 43 51 57 60 07 26 30 39 50 56 65 65 67 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 ω ρ ε 23 λ ω < 1 ω < 1 ω > 0 24 25 26 27 28 29 30 31 ρ 1 ρ σ b a x x i +3 x i
More information,!! #! > 1? = 4!! > = 5 4? 2 Α Α!.= = 54? Β. : 2>7 2 1 Χ! # % % ( ) +,. /0, , ) 7. 2
! # %!% # ( % ) + %, ). ) % %(/ / %/!! # %!! 0 1 234 5 6 2 7 8 )9!2: 5; 1? = 4!! > = 5 4? 2 Α 7 72 1 Α!.= = 54?2 72 1 Β. : 2>7 2 1 Χ! # % % ( ) +,.
More information(CIP) : / :,, :,2000.5 ISBN 7-04 - 008822-3 - - N - 42 CIP (2000)60397 55 100009 010-64054588 010-64014048 / 8501168 1/ 32 7.875
( ) (CIP) : / :,, :,2000.5 ISBN 7-04 - 008822-3 - - N - 42 CIP (2000)60397 55 100009 010-64054588 010-64014048 http:/ / www.hep.edu.cn 8501168 1/ 32 7.875 190 000 8.40, ( ) 1 16 16 16 18 21 22 24 24 24
More informationuntitled
4 y l y y y l,, (, ) ' ( ) ' ( ) y, y f ) ( () f f ( ) (l ) t l t lt l f ( t) f ( ) t l f ( ) d (l ) C f ( ) C, f ( ) (l ) L y dy yd π y L y cosθ, π θ : siθ, π yd dy L [ cosθ cosθ siθ siθ ] dθ π π π si
More information3978 30866 4 3 43 [] 3 30 4. [] . . 98 .3 ( ) 06 99 85 84 94 06 3 0 3 9 3 0 4 9 4 88 4 05 5 09 5 8 5 96 6 9 6 97 6 05 7 7 03 7 07 8 07 8 06 8 8 9 9 95 9 0 05 0 06 30 0 .5 80 90 3 90 00 7 00 0 3
More information微积分 授课讲义
2018 10 aiwanjun@sjtu.edu.cn 1201 / 18:00-20:20 213 14:00-17:00 I II Taylor : , n R n : x = (x 1, x 2,..., x n ) R; x, x y ; δ( ) ; ; ; ; ; ( ) ; ( / ) ; ; Ů(P 1,δ) P 1 U(P 0,δ) P 0 Ω P 1: 1.1 ( ). Ω
More information8 9 8 Δ 9 = 1 Η Ι4 ϑ< Κ Λ 3ϑ 3 >1Ε Μ Ε 8 > = 8 9 =
!! % & ( & ),,., / 0 1. 0 0 3 4 0 5 3 6!! 7 8 9 8!! : ; < = > :? Α 4 8 9 < Β Β : Δ Ε Δ Α = 819 = Γ 8 9 8 Δ 9 = 1 Η Ι4 ϑ< Κ Λ 3ϑ 3 >1Ε 8 9 0 Μ Ε 8 > 9 8 9 = 8 9 = 819 8 9 =
More information: ; # 7 ( 8 7
(! # % & ( ) +,. / +. 0 0 ) 1. 2 3 +4 1/,5,6 )/ ) 7 7 8 9 : ; 7 8 7 # 7 ( 8 7 ; ;! #! % & % ( # ) % + # # #, # % + &! #!. #! # # / 0 ( / / 0! #,. # 0(! #,. # 0!. # 0 0 7 7 < = # ; & % ) (, ) ) ) ) ) )!
More information) & ( +,! (# ) +. + / & 6!!!.! (!,! (! & 7 6!. 8 / ! (! & 0 6! (9 & 2 7 6!! 3 : ; 5 7 6! ) % (. ()
! # % & & &! # % &! ( &! # )! ) & ( +,! (# ) +. + / 0 1 2 3 4 4 5 & 6!!!.! (!,! (! & 7 6!. 8 / 6 7 6 8! (! & 0 6! (9 & 2 7 6!! 3 : ; 5 7 6! ) % (. () , 4 / 7!# + 6 7 1 1 1 0 7!.. 6 1 1 2 1 3
More informationt H θ m [] Q Q q [] 9. 69kJ g q 32.0 620kJmol - 1 0. 500g mol C(s) 1 2 O (g) = CO(g) 2 SI n mol H 2H+H22H2+O2 [N2H41+O2g N2g+2H2O1] 1.2.3 qp qv [4] 1 C( ) O 2 (g) = CO(g), ( 2), 2 CO(g) CO (g),co(g) +
More informationuntitled
6.1 ( ) 6.1.1 1. θ (6-1) θ (V w ) V S w (6-) S w (V ) θ n S w 1 θ ns w (6-3) 179 6-1 ( ) ( ) p c pc = pa pw (6-4) p p 1135Pa( a ) p c p w w p a = (6-5) ( ) 6-6 γ pc pw h = = (6-7) c γ γ ψ ψ = pw γ > (6-8)
More informationB = F Il 1 = 1 1 φ φ φ B = k I r F Il F k I 2 = l r 2 10 = k 1 1-7 2 1 k = 2 10-7 2 B = ng Il. l U 1 2 mv = qu 2 v = 2qU m = 2 19 3 16. 10 13. 10 / 27 167. 10 5 = 5.0 10 /. r = m ν 1 qb r = m ν qb
More informationΒ 8 Α ) ; %! #?! > 8 8 Χ Δ Ε ΦΦ Ε Γ Δ Ε Η Η Ι Ε ϑ 8 9 :! 9 9 & ϑ Κ & ϑ Λ &! &!! 4!! Μ Α!! ϑ Β & Ν Λ Κ Λ Ο Λ 8! % & Π Θ Φ & Ρ Θ & Θ & Σ ΠΕ # & Θ Θ Σ Ε
! #!! % & ( ) +,. /. 0,(,, 2 4! 6! #!!! 8! &! % # & # &! 9 8 9 # : : : : :!! 9 8 9 # #! %! ; &! % + & + & < = 8 > 9 #!!? Α!#!9 Α 8 8!!! 8!%! 8! 8 Β 8 Α ) ; %! #?! > 8 8 Χ Δ Ε ΦΦ Ε Γ Δ Ε Η Η Ι Ε ϑ 8 9 :!
More information1 2 1.1............................ 2 1.2............................... 3 1.3.................... 3 1.4 Maxwell.................... 3 1.5.......................... 4 1.6............................ 4
More information) Μ <Κ 1 > < # % & ( ) % > Χ < > Δ Χ < > < > / 7 ϑ Ν < Δ 7 ϑ Ν > < 8 ) %2 ): > < Ο Ε 4 Π : 2 Θ >? / Γ Ι) = =? Γ Α Ι Ρ ;2 < 7 Σ6 )> Ι= Η < Λ 2 % & 1 &
! # % & ( ) % + ),. / & 0 1 + 2. 3 ) +.! 4 5 2 2 & 5 0 67 1) 8 9 6.! :. ;. + 9 < = = = = / >? Α ) /= Β Χ Β Δ Ε Β Ε / Χ ΦΓ Χ Η Ι = = = / = = = Β < ( # % & ( ) % + ),. > (? Φ?? Γ? ) Μ
More information... II... III A A A.2...
ICS 13.200 X XX DZ DZ Specfcaton of desgn and constructon for landslde stablzaton - - - - 1 ... II... III 1... 1 2... 1 3... 1 4... 3 5... 4 6... 7 7... 12 8... 18 9... 24 10... 28 11... 32 12... 35 13...
More informationⅠ Ⅱ 1 2 Ⅲ Ⅳ
Ⅰ Ⅱ 1 2 Ⅲ Ⅳ !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
More informationuntitled
+ lim = + + lim = + lim ( ) + + + () f = lim + = + = e cos( ) = e f + = e cos = e + e + + + sin + = = = = = + = + cos d= () ( sin ) 8 cos sin cos = ( ) ( sin ) cos + d= ( + ) = cos sin cos d sin d 4 =
More information> # ) Β Χ Χ 7 Δ Ε Φ Γ 5 Η Γ + Ι + ϑ Κ 7 # + 7 Φ 0 Ε Φ # Ε + Φ, Κ + ( Λ # Γ Κ Γ # Κ Μ 0 Ν Ο Κ Ι Π, Ι Π Θ Κ Ι Π ; 4 # Ι Π Η Κ Ι Π. Ο Κ Ι ;. Ο Κ Ι Π 2 Η
1 )/ 2 & +! # % & ( ) +, + # # %. /& 0 4 # 5 6 7 8 9 6 : : : ; ; < = > < # ) Β Χ Χ 7 Δ Ε Φ Γ 5 Η Γ + Ι + ϑ Κ 7 # + 7 Φ 0 Ε Φ # Ε + Φ, Κ + ( Λ # Γ Κ Γ #
More information9!!!! #!! : ;!! <! #! # & # (! )! & ( # # #+
! #! &!! # () +( +, + ) + (. ) / 0 1 2 1 3 4 1 2 3 4 1 51 0 6. 6 (78 1 & 9!!!! #!! : ;!! ? &! : < < &? < Α!!&! : Χ / #! : Β??. Δ?. ; ;
More information8 9 < ; ; = < ; : < ;! 8 9 % ; ϑ 8 9 <; < 8 9 <! 89! Ε Χ ϑ! ϑ! ϑ < ϑ 8 9 : ϑ ϑ 89 9 ϑ ϑ! ϑ! < ϑ < = 8 9 Χ ϑ!! <! 8 9 ΧΧ ϑ! < < < < = 8 9 <! = 8 9 <! <
! # % ( ) ( +, +. ( / 0 1) ( 2 1 1 + ( 3 4 5 6 7! 89 : ; 8 < ; ; = 9 ; ; 8 < = 9! ; >? 8 = 9 < : ; 8 < ; ; = 9 8 9 = : : ; = 8 9 = < 8 < 9 Α 8 9 =; %Β Β ; ; Χ ; < ; = :; Δ Ε Γ Δ Γ Ι 8 9 < ; ; = < ; :
More information. () ; () ; (3) ; (4).. () : P.4 3.4; P. A (3). () : P. A (5)(6); B. (3) : P.33 A (9),. (4) : P. B 5, 7(). (5) : P.8 3.3; P ; P.89 A 7. (6) : P.
() * 3 6 6 3 9 4 3 5 8 6 : 3. () ; () ; (3) (); (4) ; ; (5) ; ; (6) ; (7) (); (8) (, ); (9) ; () ; * Email: huangzh@whu.edu.cn . () ; () ; (3) ; (4).. () : P.4 3.4; P. A (3). () : P. A (5)(6); B. (3) :
More information. /!Ι Γ 3 ϑκ, / Ι Ι Ι Λ, Λ +Ι Λ +Ι
! # % & ( ) +,& ( + &. / 0 + 1 0 + 1,0 + 2 3., 0 4 2 /.,+ 5 6 / 78. 9: ; < = : > ; 9? : > Α
More informationⅠⅡⅢ Ⅳ
ⅠⅡⅢ Ⅳ ! "!"#$%&!!! !"#$%& ()*+,!"" *! " !! " #$%& ( Δ !"#$%& ()*+,!"" * !! " #$%& ( !"#$%& ()*+,!"" * !! " #$%& ( !"#$%& ()*+,!"" * !! " #$%& (! # !"#$%& ()*+,!"" * !! " #$%& ( 1 1 !"#$%& ()*+,!"" *
More informationuntitled
[] [] [] 15.1 1 2 Cu 2+ 2e=Cu Zn 2+ 2e=Zn 2H + 2eH 2 Cu2e=Cu 2+ Ni2e=Ni 2+ 2OH 2e=H 2 O 1/2O 2 2Cl 2e=Cl 2 1 1. 2. 15.2 z+ ze l H 3 O + e 2 1 H 2 O 2a H 2 O e 2 1 OH 2b O 2 2H 2 O 4e4OH 3 z+ ze 4 z+ (zh)e
More information[2001]1 SL SL
ICS93.160 P58 SL SL44 2006 SL44 93 Regulation for calculating design flood of water resources and hydropower projects 2006-09-09 2006-10-01 [2001]1 SL44-93 10 1998 7 14 93 3 SL44-93 1 2 1...1 2...3 2.1...3
More information= Υ Ξ & 9 = ) %. Ο) Δ Υ Ψ &Ο. 05 3; Ι Ι + 4) &Υ ϑ% Ο ) Χ Υ &! 7) &Ξ) Ζ) 9 [ )!! Τ 9 = Δ Υ Δ Υ Ψ (
! # %! & (!! ) +, %. ( +/ 0 1 2 3. 4 5 6 78 9 9 +, : % % : < = % ;. % > &? 9! ) Α Β% Χ %/ 3. Δ 8 ( %.. + 2 ( Φ, % Γ Η. 6 Γ Φ, Ι Χ % / Γ 3 ϑκ 2 5 6 Χ8 9 9 Λ % 2 Χ & % ;. % 9 9 Μ3 Ν 1 Μ 3 Φ Λ 3 Φ ) Χ. 0
More information2.1 1980 1992 % 80 81 82 83 84 85 86 87 88 89 90 91 92 81.9 69.5 68.7 66.6 64.7 66.1 65.5 63.1 61.4 61.3 65.6 65.8 67.1 5.0 12.0 14.2 10.9 13.0 12.9 13.0 15.0 15.8 13.8 10.9 12.7 17.3 13.1 18.6 17.1 22.5
More information1 s = v t + at, 0 v = v + at 0. 1 3.0 36 s = v t + at a 0 1 F ma a s v t at s 0 F f 1 a m = mgsin θ µ mg cosθ g sinθ µ cosmθ 1 s = v t + at 0 1 v tsinθ µ cosθ 0 1 1 1.0 5.0 9.8 50 0 04 3.. 5 57
More informationx iy x y 2 2 + value I / 2 0 R X 2 2 + é t S = vdt 2 t l é x iy i x y x = 1, ( é ü 3 17320508 =. é é 2EvM ü
More information4 # = # 4 Γ = 4 0 = 4 = 4 = Η, 6 3 Ι ; 9 Β Δ : 8 9 Χ Χ ϑ 6 Κ Δ ) Χ 8 Λ 6 ;3 Ι 6 Χ Δ : Χ 9 Χ Χ ϑ 6 Κ
! # % & & ( ) +, %. % / 0 / 2 3! # 4 ) 567 68 5 9 9 : ; > >? 3 6 7 : 9 9 7 4! Α = 42 6Β 3 Χ = 42 3 6 3 3 = 42 : 0 3 3 = 42 Δ 3 Β : 0 3 Χ 3 = 42 Χ Β Χ 6 9 = 4 =, ( 9 6 9 75 3 6 7 +. / 9
More informationUDC
Technical code for groung treatment of buildings JGJ 79-2002 J 220-2002 Technical code for groung treatment of buildings JGJ 79-2002 2 0 0 3 1 1 64 JGJ79 2002 2003 1 1 3.0.5 3.0.6 4.4.2 5.4.2 6.1.2 6.3.5
More informationttian
T = l g = a - b a ϕ ϕ ϕ ϕ ϕ ϕ SiO SiO 65% SiO 52% SiO 52 45% SiO 45% 20 45% 10% 50% 95% 2.5 2.7 2.7 2.8 2.9 3.1 3.1 3.5 S0=1.94
More informationTHERMO-6.PDF
v ( ) a = dv ln θ T ln θ S T ln θ θ 90 o θ = κ mb= R C ( θ) ( ) ln = ln T κ ln + const d κ d d log a = q = Tds ds = c d lnθ a = c Td ln θ = c teh. teh. 45 o ln T 45 o ( ) = ( ) + θ + = ( ) + κ κ κ δa =
More information, & % # & # # & % & + # & # # # & # % #,
! # #! % # & # & & ( ( # ) % , & % # & # # & % & + # & # # # & # % #, # % % # % # ) % # % % # % # # % # % # + # % ( ( # % & & & & & & % & & # % # % & & % % % . % # / & & # 0 ) & # % & % ( # # & & & # #
More information5 550A 5 550A 6 38A 5 m 3.39 m 4 800A 5 45A c v n n c / v n c / v sina / sin β = v / v, v Ia 4 λ m m v / c m v 0 n sin( u) S r S - n sin u sin u OA( S) sin( u ) = OA/ S ( ) n n n n S S
More informationUDC
Technical code for groung treatment of buildings JGJ 79-2002 J 220-2002 2002 1 1 @ www.sinoaec.com JGJ 79-2002 @ Technical code for groung treatment of buildings JGJ 79-2002 2 0 0 3 1 1 2 0 0 2 2 2 64
More information1
相對內容大綱 : 高考課程大網第一章第 3 節 參考 : 高級程度物理第一冊第七章 6.0 6. 6. 6.3 6.4 6.5 6.6 6.7 6.8 6.9 6.0 6. 6.0 CD 6. P ( x, y (pola coodinate P (,θ ( 6.. P θ OP x B s θ P θ (angula position θ θ [ θ ](angula displacement θ
More informationkoji-13.dvi
26 13 1, 2, 3, 4, 5, 6, 7 1 18 1. xy D D = {(x, y) y 2 x 4 y 2,y } x + y2 dxdy D 2 y O 4 x 2. xyz D D = {(x, y, z) x 1, y x 2, z 1, y+ z x} D 3. [, 1] [, 1] (, ) 2 f (1)
More information9 : : ; 7 % 8
! 0 4 1 % # % & ( ) # + #, ( ) + ) ( ). / 2 3 %! 5 6 7! 8 6 7 5 9 9 : 6 7 8 : 17 8 7 8 ; 7 % 8 % 8 ; % % 8 7 > : < % % 7! = = = : = 8 > > ; 7 Ε Β Β % 17 7 :! # # %& & ( ) + %&, %& ) # 8. / 0. 1 2 3 4 5
More informationuntitled
00, + lim l[ ] =. ( + lim[ ] = lim[ ] ( + i e ( = ( + lim l[ ] = l e = ( 4 (, (, (, 0 d f d D= D + D, d f d + d f d =. 0 D = (, 0,, 4 D = (,, 4 D ( D =, 0,. 4 0 0 4 ( + ( = ( d f, d d f, d d f, d. - =
More information工程硕士网络辅导第一讲
< > < R R [ si t R si cos si cos si cos - sisi < si < si < < δ N δ { < δ δ > } www.tsighututor.com 6796 δ < < δ δ N δ { < < δ δ > b { < < b R} b] { b R} [ { > R} { R} } [ b { < b R} ] { b R} { R} X X Y
More informationuntitled
6 + a lim = 8, a =. a l. a a + a a a a lim = lim + = e, a a a e = 8 a= l ( 6,, ), 4 y+ z = 8. + y z = ( 6,, ) 4 y z 8 a ( 6,, ) + = = { } i j k 4,,, s = 6 = i+ j k. 4 ( ) ( y ) ( z ) + y z =. + =, () y
More informationuntitled
/ ux ( [ x ρ + x ρ ] ρ ux ( ρux ( ρ ρ( x ρ + x ρ 3 u ( δ δ x(, ( (, δ δ + ρ δ (, ρ u( v(, / ( δ + δ δ α δ δ x( α, α (( α,( α δ δ ( α + ( α δ δ (, δ δ ( + ( x(, δ δ x(, ( + δ δ ( + ( v( α, α α α δ δ / δ
More informationé SI 12g C = 6 12 = 1 H2( g) + O2( g) H2O( l) + 286kJ ( 1) 2 1 1 H 2( g) + O2( g) H2O( l) H = 286kJ mol ( 2) 2 1 N 2 ( g) + O2( g) NO 2 ( g) 34kJ 2 1 1 N 2 ( g) + O2( g) NO 2 ( g) H = + 34kJ mol 2 1 N
More informationstexb08.dvi
B 1 1.1 V N 1 H = p 2 i 2m i 1. Z = β =(k B T ) 1. 1 h 3N N! exp( βh)d p 1 d p N d x 1 x N 2. F ( F = k B T log Z ) 3. ( ) F p = V T 1.2 H μ μh μh N H T 1. Z Z 1 N Z 1 Z 2. F S ( ) F S = T 3. U = F + TS
More information() (n = 4 3 )?( ) ( H) ( n) 0 H H,. , L. f(f < L 4 ),.? L L L L. + fl;. fl; 4 4 M f, = fm r (4) = E 3 - E h L L, 3 ; L L = P E S, ;, ;, ;,. 5 f. 4 u + v = f, u = 4v; 4v + v = f, v = 5 4 f..()80
More information5 (Green) δ
2.............................. 2.2............................. 3.3............................. 3.4........................... 3.5...................... 4.6............................. 4.7..............................
More informationΑ? Β / Χ 3 Δ Ε/ Ε 4? 4 Ε Φ? ΧΕ Γ Χ Η ΙΙ ϑ % Η < 3 Ε Φ Γ ΕΙΙ 3 Χ 3 Φ 4 Κ? 4 3 Χ Λ Μ 3 Γ Ε Φ ) Μ Ε Φ? 5 : < 6 5 % Λ < 6 5< > 6! 8 8 8! 9 9 9! 9 =! = 9!
# %!!! ( ) ( +, +. ( / 0 1) ( 21 1) ( 2 3 / 4!! 5 6 7 7! 8 8 9 : ; < 9 = < < :! : = 9 ; < = 8 9 < < = 9 8 : < >? % > % > % 8 5 6 % 9!9 9 : : : 9 Α % 9 Α? Β / Χ 3 Δ Ε/ Ε 4? 4 Ε Φ? ΧΕ Γ Χ Η ΙΙ ϑ % Η < 3
More informationuntitled
Part A Part A CH......... A- CH..... A-6 CH3......... A- CH4... A-3 CH5... A-7 CH6... A-3 立 數 http://www. 立.tw Part A CH. ODE ) dy g f g f g dy f d d y general solution) g dy f d + c dt ) k T TA ) dt T
More information第12章_下_-随机微分方程与扩散.doc
Ω, F, P } B B ω, ω Ω { B ω ω Φ ω Φ Φ Φ ω ω B ω Φ Φ ω B ω [, ] < L < l l J l ω Φ ω B ω B ω Φ ω B ω l J ω l J ω Φ B l J ω l ω J 343 J J ω, ω Ω } { B : B J B ε > l P ω η ω > ε J Φ ω B ω Φ B η ΦB J, ] B B
More information(r s) {φ r1, φ r2,, φ rn } {φ s1, φ s2,, φ sn } u r (t) u s (t). F st ι u st u st k 1 ι φ i q st i (6) r β u r β u r u r(t) max u st r φ
3 351 1) 2) ( 100083)... TU311.3 doi 10.6052/1000-0879-13-151 A. [1-3]. 180.. [4]..... 2013 04 18 1 2013 05 23. 1 N mü(t) + c u(t) + ku(t) ι sin θt (1) m, c k N N m u(t) u(t) ü(t) N ι N θ. (ω i, φ i ).
More informationM ( ) K F ( ) A M ( ) 1815 (probable error) F W ( ) J ( ) n! M ( ) T ( ) L ( ) T (171
1 [ ]H L E B ( ) statistics state G (150l--1576) G (1564 1642) 16 17 ( ) C B (1623 1662) P (1601--16S5) O W (1646 1716) (1654 1705) (1667--1748) (1687--H59) (1700 1782) J (1620 1674) W (1623 1687) E (1656
More information( ) (! +)! #! () % + + %, +,!#! # # % + +!
!! # % & & & &! # # % ( ) (! +)! #! () % + + %, +,!#! # # % + +! ! %!!.! /, ()!!# 0 12!# # 0 % 1 ( ) #3 % & & () (, 3)! #% % 4 % + +! (!, ), %, (!!) (! 3 )!, 1 4 ( ) % % + % %!%! # # !)! % &! % () (! %
More information3 4 Ψ Ζ Ζ [, Β 7 7>, Θ0 >8 : Β0 >, 4 Ε2 Ε;, ] Ε 0, 7; :3 7;,.2.;, _ & αε Θ:. 3 8:,, ), β & Φ Η Δ?.. 0?. χ 7 9 Ε >, Δ? Β7 >7 0, Τ 0 ΚΚ 0 χ 79 Ε >, Α Ε
(! # # %& ) +,./ 0 & 0 1 2 / & %&( 3! # % & ( ) & +, ), %!,. / 0 1 2. 3 4 5 7 8 9 : 0 2; < 0 => 8?.. >: 7 2 Α 5 Β % Χ7 Δ.Ε8 0Φ2.Γ Φ 5 Η 8 0 Ι 2? : 9 ϑ 7 ϑ0 > 2? 0 7Ε 2?. 0. 2 : Ε 0 9?: 9 Κ. 9 7Λ /.8 720
More informationJ = m i r 2 i i ϕ 1 = Rg R 2πR R T = = 2π = 84. 4 min ( 1) g 1 T = 2π m / k k T = 2π m/ k = 2π R / g = 84. 4min ( 2) T = 2π l / g ( 3) / 0 20 40 60 80 100 120 /Pa 600.66 2338.1
More information: ; 8 Β < : Β Δ Ο Λ Δ!! Μ Ν : ; < 8 Λ Δ Π Θ 9 : Θ = < : ; Δ < 46 < Λ Ρ 0Σ < Λ 0 Σ % Θ : ;? : : ; < < <Δ Θ Ν Τ Μ Ν? Λ Λ< Θ Ν Τ Μ Ν : ; ; 6 < Λ 0Σ 0Σ >
! # %& ( +, &. / ( 0 # 1# % & # 2 % & 4 5 67! 8 9 : ; < 8 = > 9? 8 < 9? Α,6 ΒΧ : Δ 8Ε 9 %: ; < ; ; Δ Φ ΓΗ Ιϑ 4 Κ6 : ; < < > : ; : ;!! Β : ; 8 Β < : Β Δ Ο Λ Δ!! Μ Ν : ; < 8 Λ Δ Π Θ 9 : Θ = < : ; Δ < 46
More information2 1 4 % 19.5 15 19.2 24.3 27 25.0 55.2 58 55.8 16.9 19 16.3 30.6 33 32.6 52.5 48 51.1 54.8 52 54.05 45.2 40 45.95 8 1 2 3 P nmu / s 3 a P V b RT r 2 dp dt Q = T(V V 1 2
More information或 者 紅 外 線 都 很 明 顯, 顯 示 它 是 又 厚 又 高 的 雲 (C) 丙 處 的 雲 為 對 流 發 展 旺 盛 的 積 雨 雲, 所 以 在 可 見 光 雲 圖 較 明 顯, 而 紅 外 線 雲 圖 較 暗 淡 (D) 甲 處 的 雲 主 要 是 低 層 雲, 所 以 在 可 見
高 二 單 元 5 萬 象 風 雲 地 球 科 學 歷 屆 學 測 試 題 彙 整 泰 宇 基 礎 地 球 科 學 下 冊 章 節 第 六 章 觀 風 雲 6-1 氣 象 觀 測 6-2 氣 象 預 報 第 七 章 多 變 的 天 氣 7-1 成 雲 致 雨 7-2 大 氣 運 動 1. 臺 灣 地 區 約 在 北 緯 二 十 多 度, 此 地 區 地 面 氣 象 觀 測 坪 內 安 置 之 百 葉
More information% & :?8 & : 3 ; Λ 3 3 # % & ( ) + ) # ( ), ( ) ). ) / & /:. + ( ;< / 0 ( + / = > = =? 2 & /:. + ( ; < % >=? ) 2 5 > =? 2 Α 1 Β 1 + Α
# % & ( ) # +,. / 0 1 2 /0 1 0 3 4 # 5 7 8 / 9 # & : 9 ; & < 9 = = ;.5 : < 9 98 & : 9 %& : < 9 2. = & : > 7; 9 & # 3 2
More informationtbjx0164ZW.PDF
F = k Q Q r F = k Q = k Q r r Q Q = Fr k = C 0 5 C 9 0 5 Q 0 3 n = = 9 = 65. 0 e 6. 0 4 3 A B 7 7 9 6 C D 7 7 F = k q 7q = k 7q r r q + 7q = 4q F = k 4q 4q = k 6q r r F = 6 F 7 7q q = 3q s c = t s c =
More information第一章.doc
= c < < + + = S = c( ) = k =, k =,,, Λ < < + = 4 = = = = 4 k = k =,,, Λ X R X X = f () X X = f ( ) k = + k =,,, Λ = f () X X f ( ) = = = = n n = an + an +... + a + a a n =a +a +a = a + a + a a n f ( )
More information