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世忒班
6 years ago
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2 TUDY OF A TEPPING MOTOR PEED-UBDIVIION CONTRO YTEM ABTRACT This paper presens a speed-subdivision conrol and drive sysem. I is used on railway locomoives o improve heir performance by solving some disadvanages of he elder sysem. This new sysem of elecrical acceleraors is applying o he high-performance speed conrol of railway locomoives. I is consised of elecrical driver conroller, driver source, and resisor box for curren limiaion, mechanical drive machines and sepping moor. In his paper he sysem operaion principle is analyzed a lengh. Also houghfully considered is he sepping moor dynamic model. And he sysem performance is furher improved afer close-loop conrol sraegy and some novel circuis adoped. I can flexibly and smoohly conrol railway locomoives o accelerae, decelerae or run a a cerain speed, which is exacly he chief objecive of locomoive seering. Up o nowadays his sysem has been applied o many railway locomoives and has worked saisfyingly. And i also has widely gained he users recommendaion. A las an up-o-dae conrol idea is presened and explored in a nushell. And i provides a novel way o

3 improve he railway locomoive performance. KEY WORD: speed subdivision conrol, sepping Moor, driver source

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48 = d /d= ] sin[ = i K d d D d d J a T δθ δθ δθ 5-8 ] sin[ δθ δθ = 5-9 = i K d d D d d J a T δθ δθ δθ 5- = o- i 5- i =, 5- i a i K o i K d o d D d o d J T a T θ θ θ θ = 5- i a i K o i K D J T a T θ θ = 5-3 n J D n a i K D J a i K i o G T T ω ω θ θ = = = 5-4 J T J a i K n k T = = ω T k 5..

49 aa = cos θ 5-5 bb = cos θ 5-6 ab = cos θ 5-7 daa dbb dab Te = i a i b iaib dθ dθ dθ d θ dθ J D i asin θ d d 5-9 i b sin θ iaib sin θ = d aaia d abib Ua Ra ia = 5- d d d bbib d abia U b Rbib = 5- d d =, θ =, dθ = d δθ δ i a δ i b θ = δθ 5- i a = I δ ia 5-3 i b = I δ i b 5-4 I i a =i b =I, cos θ = cos δθ 5-5

50 = sin sin δθ θ 5-6 δθ cos = δθ 5-7 sin δθ δθ = cos sin sin sin δθ δθ θ = = 5-9 sin cos cos cos δθ δθ θ = = 5-3 cos sin sin sin δθ δθ θ = = 5-3 sin cos cos cos δθ δθ θ = = 5-3 sin sin Z δθ δθ θ = = 5-33 cos cos = = δθ θ ] [ sin cos = ib i I ri Z d d D d d J a δ δ δθ δθ δθ 5-35

51 ia δ δθ ] [ ia δ ] [ sin ] [ ] [ cos ] [ = d d I ib d d ia d d ia R δθ δ δ δ 5-36 ] [ sin ] [ ] [ cos ] [ = d d I ia d d ib d d ib R δθ δ δ δ =, θ θ = = i, = d dθ i a =i b =I, θ δθ 5-38 i i a a δ 5-39 i i b b δ R I R I i i v i i b a = = = ] [ sin ] cos [ ] [ sin θ θ θ θ 5-4 cos v = 5-4

52 s i θ θ δθ = θ θ = = i = d dθ vn v vn v v v i vn v v v R k J D R J D R k J D R J D R 3 ω ω θ ω θ = 5-43 J ri Z I k vn v v cos cos sin ω = = = G vn v vn v v v v i R k J D R J D R nv R G 3 ω ω ω θ θ = =

53 θ ω = 5-46 n G = θ i ζω n ω n ζ D ζ = 5-47 Jω n 5-46 ω n ζ ζ.5., i a i b R R [ k n ] ω = 3 v n ω 5-48 R/----- Kv n----- R/ Kv n K 5-48

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元 [ 所 17-1-2-3] IA27 ( D ) 下列何項情況, 其夫妻所得可免合併申報? (A) 當年度結婚 (B) 當年度離婚 (C) 妻 58 歲, 夫 62 歲無所得受其子扶養 (D) 以上皆是 [ 所 17-1-1]

元 [ 所 17-1-2-3] IA27 ( D ) 下列何項情況, 其夫妻所得可免合併申報? (A) 當年度結婚 (B) 當年度離婚 (C) 妻 58 歲, 夫 62 歲無所得受其子扶養 (D) 以上皆是 [ 所 17-1-1] 綜合所得稅選擇題題庫 IA01 ( A ) 非中華民國境內居住之個人, 取有中華民國境內銀行給付之活期儲蓄存款利息所得, 依據所得稅法規定, 應否課徵綜合所得稅? (A) 應就源扣繳 (B) 全年在 27 萬元以下免納所得稅 (C) 應該辦理結算申